WORM Solution
RUNNING FLOOR
WORM row 5
Unlocks
w54 solved
Active cores1, 4
Program lines15
DetailWORM row 5
Walkthrough
RUNNING FLOOR: OUT = the smallest input seen so far (never resets).
Two-row rack: input tap rides core 1 (UP), output tap rides core 4 (DOWN).
Core 1 fans each input DOWN twice, the way the peak-hold pipeline does: the
compare consumes one copy, the chosen value needs the other.
Core 4 keeps the running floor in ACC, primed to +999 so the first input
always lowers it. Each step: BAK = floor, ACC = floor: v (first copy). If the
result is below 0 the floor is already smaller, so keep it (discard the second
copy and swap the floor back); otherwise the new value is the floor (take the
second copy). The loop wraps via JMP M, so the prime runs only once.
Rack Solution
# RUNNING FLOOR: OUT = the smallest input seen so far (never resets).
# Two-row rack: input tap rides core 1 (UP), output tap rides core 4 (DOWN).
# Core 1 fans each input DOWN twice, the way the peak-hold pipeline does: the
# compare consumes one copy, the chosen value needs the other.
# Core 4 keeps the running floor in ACC, primed to +999 so the first input
# always lowers it. Each step: BAK = floor, ACC = floor: v (first copy). If the
# result is below 0 the floor is already smaller, so keep it (discard the second
# copy and swap the floor back); otherwise the new value is the floor (take the
# second copy). The loop wraps via JMP M, so the prime runs only once.
@1
MOV ACC, UP
MOV DOWN, ACC
MOV DOWN, ACC
@4
MOV ACC, 999
M: SAV
SUB UP
JL K
MOV ACC, UP
JMP E
K: MOV NIL, UP
XCH
E: MOV DOWN, ACC
JMP M