CRACK Solution
Sum Times Three
CRACK checksum times 3

Prerequisites
Unlocks
ACE
Techniquechecksum times 3
Rulenonzero
SampleACE
Walkthrough
Recover the accepted input below, then submit it to the CRACK verifier.
Reject Samples
- AC
- ACES
- ace
- BCE
Verifier Listing
; llama_mul_sum: checksum times three. The three input bytes are summed, the
; total is multiplied by 3, and the product is checked against the stored target.
; Technique: additive checksum * 3. r0 = 1 on accept. Accept rule: nonzero.
;
; sample "ACE": 65 + 67 + 69 = 201; 201 * 3 = 603. In 8-bit math the product
; wraps mod 256: 603 & 0xFF = 0x5B, the byte the check compares against. The sum
; 201 fits in a byte, so the running total never overflows before the multiply.
len r2
cmp r2, 3
jnz bad ; fixed-length puzzle: exactly 3 bytes
mov r3, 0 ; r3 = running sum
mov r7, 0 ; r7 = index
loop: cmp r7, r2
jge tally ; summed all three -> multiply
ldb r0, [r7]
add r3, r0 ; sum += input[r7]
inc r7
jmp loop
tally: mov r0, r3
mul r0, 3 ; total * 3 (mod 256)
cmp r0, 0x5b ; 603 & 0xFF
jnz bad
mov r0, 1
ret
bad: mov r0, 0
ret